| A brief CRC tutorial. |
| |
| A CRC is a long-division remainder. You add the CRC to the message, |
| and the whole thing (message+CRC) is a multiple of the given |
| CRC polynomial. To check the CRC, you can either check that the |
| CRC matches the recomputed value, *or* you can check that the |
| remainder computed on the message+CRC is 0. This latter approach |
| is used by a lot of hardware implementations, and is why so many |
| protocols put the end-of-frame flag after the CRC. |
| |
| It's actually the same long division you learned in school, except that |
| - We're working in binary, so the digits are only 0 and 1, and |
| - When dividing polynomials, there are no carries. Rather than add and |
| subtract, we just xor. Thus, we tend to get a bit sloppy about |
| the difference between adding and subtracting. |
| |
| Like all division, the remainder is always smaller than the divisor. |
| To produce a 32-bit CRC, the divisor is actually a 33-bit CRC polynomial. |
| Since it's 33 bits long, bit 32 is always going to be set, so usually the |
| CRC is written in hex with the most significant bit omitted. (If you're |
| familiar with the IEEE 754 floating-point format, it's the same idea.) |
| |
| Note that a CRC is computed over a string of *bits*, so you have |
| to decide on the endianness of the bits within each byte. To get |
| the best error-detecting properties, this should correspond to the |
| order they're actually sent. For example, standard RS-232 serial is |
| little-endian; the most significant bit (sometimes used for parity) |
| is sent last. And when appending a CRC word to a message, you should |
| do it in the right order, matching the endianness. |
| |
| Just like with ordinary division, you proceed one digit (bit) at a time. |
| Each step of the division you take one more digit (bit) of the dividend |
| and append it to the current remainder. Then you figure out the |
| appropriate multiple of the divisor to subtract to being the remainder |
| back into range. In binary, this is easy - it has to be either 0 or 1, |
| and to make the XOR cancel, it's just a copy of bit 32 of the remainder. |
| |
| When computing a CRC, we don't care about the quotient, so we can |
| throw the quotient bit away, but subtract the appropriate multiple of |
| the polynomial from the remainder and we're back to where we started, |
| ready to process the next bit. |
| |
| A big-endian CRC written this way would be coded like: |
| for (i = 0; i < input_bits; i++) { |
| multiple = remainder & 0x80000000 ? CRCPOLY : 0; |
| remainder = (remainder << 1 | next_input_bit()) ^ multiple; |
| } |
| |
| Notice how, to get at bit 32 of the shifted remainder, we look |
| at bit 31 of the remainder *before* shifting it. |
| |
| But also notice how the next_input_bit() bits we're shifting into |
| the remainder don't actually affect any decision-making until |
| 32 bits later. Thus, the first 32 cycles of this are pretty boring. |
| Also, to add the CRC to a message, we need a 32-bit-long hole for it at |
| the end, so we have to add 32 extra cycles shifting in zeros at the |
| end of every message, |
| |
| These details lead to a standard trick: rearrange merging in the |
| next_input_bit() until the moment it's needed. Then the first 32 cycles |
| can be precomputed, and merging in the final 32 zero bits to make room |
| for the CRC can be skipped entirely. This changes the code to: |
| |
| for (i = 0; i < input_bits; i++) { |
| remainder ^= next_input_bit() << 31; |
| multiple = (remainder & 0x80000000) ? CRCPOLY : 0; |
| remainder = (remainder << 1) ^ multiple; |
| } |
| |
| With this optimization, the little-endian code is particularly simple: |
| for (i = 0; i < input_bits; i++) { |
| remainder ^= next_input_bit(); |
| multiple = (remainder & 1) ? CRCPOLY : 0; |
| remainder = (remainder >> 1) ^ multiple; |
| } |
| |
| The most significant coefficient of the remainder polynomial is stored |
| in the least significant bit of the binary "remainder" variable. |
| The other details of endianness have been hidden in CRCPOLY (which must |
| be bit-reversed) and next_input_bit(). |
| |
| As long as next_input_bit is returning the bits in a sensible order, we don't |
| *have* to wait until the last possible moment to merge in additional bits. |
| We can do it 8 bits at a time rather than 1 bit at a time: |
| for (i = 0; i < input_bytes; i++) { |
| remainder ^= next_input_byte() << 24; |
| for (j = 0; j < 8; j++) { |
| multiple = (remainder & 0x80000000) ? CRCPOLY : 0; |
| remainder = (remainder << 1) ^ multiple; |
| } |
| } |
| |
| Or in little-endian: |
| for (i = 0; i < input_bytes; i++) { |
| remainder ^= next_input_byte(); |
| for (j = 0; j < 8; j++) { |
| multiple = (remainder & 1) ? CRCPOLY : 0; |
| remainder = (remainder >> 1) ^ multiple; |
| } |
| } |
| |
| If the input is a multiple of 32 bits, you can even XOR in a 32-bit |
| word at a time and increase the inner loop count to 32. |
| |
| You can also mix and match the two loop styles, for example doing the |
| bulk of a message byte-at-a-time and adding bit-at-a-time processing |
| for any fractional bytes at the end. |
| |
| To reduce the number of conditional branches, software commonly uses |
| the byte-at-a-time table method, popularized by Dilip V. Sarwate, |
| "Computation of Cyclic Redundancy Checks via Table Look-Up", Comm. ACM |
| v.31 no.8 (August 1998) p. 1008-1013. |
| |
| Here, rather than just shifting one bit of the remainder to decide |
| in the correct multiple to subtract, we can shift a byte at a time. |
| This produces a 40-bit (rather than a 33-bit) intermediate remainder, |
| and the correct multiple of the polynomial to subtract is found using |
| a 256-entry lookup table indexed by the high 8 bits. |
| |
| (The table entries are simply the CRC-32 of the given one-byte messages.) |
| |
| When space is more constrained, smaller tables can be used, e.g. two |
| 4-bit shifts followed by a lookup in a 16-entry table. |
| |
| It is not practical to process much more than 8 bits at a time using this |
| technique, because tables larger than 256 entries use too much memory and, |
| more importantly, too much of the L1 cache. |
| |
| To get higher software performance, a "slicing" technique can be used. |
| See "High Octane CRC Generation with the Intel Slicing-by-8 Algorithm", |
| ftp://download.intel.com/technology/comms/perfnet/download/slicing-by-8.pdf |
| |
| This does not change the number of table lookups, but does increase |
| the parallelism. With the classic Sarwate algorithm, each table lookup |
| must be completed before the index of the next can be computed. |
| |
| A "slicing by 2" technique would shift the remainder 16 bits at a time, |
| producing a 48-bit intermediate remainder. Rather than doing a single |
| lookup in a 65536-entry table, the two high bytes are looked up in |
| two different 256-entry tables. Each contains the remainder required |
| to cancel out the corresponding byte. The tables are different because the |
| polynomials to cancel are different. One has non-zero coefficients from |
| x^32 to x^39, while the other goes from x^40 to x^47. |
| |
| Since modern processors can handle many parallel memory operations, this |
| takes barely longer than a single table look-up and thus performs almost |
| twice as fast as the basic Sarwate algorithm. |
| |
| This can be extended to "slicing by 4" using 4 256-entry tables. |
| Each step, 32 bits of data is fetched, XORed with the CRC, and the result |
| broken into bytes and looked up in the tables. Because the 32-bit shift |
| leaves the low-order bits of the intermediate remainder zero, the |
| final CRC is simply the XOR of the 4 table look-ups. |
| |
| But this still enforces sequential execution: a second group of table |
| look-ups cannot begin until the previous groups 4 table look-ups have all |
| been completed. Thus, the processor's load/store unit is sometimes idle. |
| |
| To make maximum use of the processor, "slicing by 8" performs 8 look-ups |
| in parallel. Each step, the 32-bit CRC is shifted 64 bits and XORed |
| with 64 bits of input data. What is important to note is that 4 of |
| those 8 bytes are simply copies of the input data; they do not depend |
| on the previous CRC at all. Thus, those 4 table look-ups may commence |
| immediately, without waiting for the previous loop iteration. |
| |
| By always having 4 loads in flight, a modern superscalar processor can |
| be kept busy and make full use of its L1 cache. |
| |
| Two more details about CRC implementation in the real world: |
| |
| Normally, appending zero bits to a message which is already a multiple |
| of a polynomial produces a larger multiple of that polynomial. Thus, |
| a basic CRC will not detect appended zero bits (or bytes). To enable |
| a CRC to detect this condition, it's common to invert the CRC before |
| appending it. This makes the remainder of the message+crc come out not |
| as zero, but some fixed non-zero value. (The CRC of the inversion |
| pattern, 0xffffffff.) |
| |
| The same problem applies to zero bits prepended to the message, and a |
| similar solution is used. Instead of starting the CRC computation with |
| a remainder of 0, an initial remainder of all ones is used. As long as |
| you start the same way on decoding, it doesn't make a difference. |