pi-futex: set PF_EXITING without taking ->pi_lock
It is a bit annoying that do_exit() takes ->pi_lock to set PF_EXITING. All
we need is to synchronize with lookup_pi_state() which saw this task
without PF_EXITING under ->pi_lock.
Change do_exit() to use spin_unlock_wait().
Signed-off-by: Oleg Nesterov <oleg@tv-sign.ru>
Acked-by: Ingo Molnar <mingo@elte.hu>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
diff --git a/kernel/exit.c b/kernel/exit.c
index 6ca1e46..3b8dfff 100644
--- a/kernel/exit.c
+++ b/kernel/exit.c
@@ -931,13 +931,13 @@
schedule();
}
+ tsk->flags |= PF_EXITING;
/*
* tsk->flags are checked in the futex code to protect against
* an exiting task cleaning up the robust pi futexes.
*/
- spin_lock_irq(&tsk->pi_lock);
- tsk->flags |= PF_EXITING;
- spin_unlock_irq(&tsk->pi_lock);
+ smp_mb();
+ spin_unlock_wait(&tsk->pi_lock);
if (unlikely(in_atomic()))
printk(KERN_INFO "note: %s[%d] exited with preempt_count %d\n",
