git grep -O -i: if the pager is 'less', pass the '-I' option
When <command> happens to be the magic string "less", today
git grep -O<command> -e<pattern>
helpfully passes +/<pattern> to less so you can navigate through
the results within a file using the n and shift+n keystrokes.
Alas, that doesn't do the right thing for a case-insensitive match,
i.e.
git grep -i -O<command> -e<pattern>
For that case we should pass --IGNORE-CASE to "less" so that n and
shift+n can move between results ignoring case in the pattern.
The original patch came from msysgit and used "-i", but that was not
due to lack of support for "-I" but it merely overlooked that it
ought to work even when the pattern contains capital letters.
Signed-off-by: Johannes Schindelin <johannes.schindelin@gmx.de>
Signed-off-by: Stepan Kasal <kasal@ucw.cz>
Helped-by: Jonathan Nieder <jrnieder@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
diff --git a/builtin/grep.c b/builtin/grep.c
index 63f8603..1892335 100644
--- a/builtin/grep.c
+++ b/builtin/grep.c
@@ -876,6 +876,9 @@
if (len > 4 && is_dir_sep(pager[len - 5]))
pager += len - 4;
+ if (opt.ignore_case && !strcmp("less", pager))
+ string_list_append(&path_list, "-I");
+
if (!strcmp("less", pager) || !strcmp("vi", pager)) {
struct strbuf buf = STRBUF_INIT;
strbuf_addf(&buf, "+/%s%s",
