remote: actually check if remote exits
When converting the git remote command to a builtin in 211c89 ("Make
git-remote a builtin"), a few calls to check if a remote exists were
converted from:
if (!exists $remote->{$name}) {
[...]
to:
remote = remote_get(argv[1]);
if (!remote)
[...]
The new check is not quite correct, because remote_get() never returns
NULL if a name is given. This leaves us with the somewhat cryptic error
message "error: Could not remove config section 'remote.test'", if we
are trying to remove a remote that does not exist, or a similar error if
we try to rename a remote.
Use the remote_is_configured() function to check whether the remote
actually exists, and die with a more sensible error message ("No such
remote: $remotename") instead if it doesn't.
Signed-off-by: Thomas Gummerer <t.gummerer@gmail.com>
Reviewed-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
diff --git a/builtin/remote.c b/builtin/remote.c
index d966262..981c487 100644
--- a/builtin/remote.c
+++ b/builtin/remote.c
@@ -634,7 +634,7 @@
rename.remote_branches = &remote_branches;
oldremote = remote_get(rename.old);
- if (!oldremote)
+ if (!remote_is_configured(oldremote))
die(_("No such remote: %s"), rename.old);
if (!strcmp(rename.old, rename.new) && oldremote->origin != REMOTE_CONFIG)
@@ -773,7 +773,7 @@
usage_with_options(builtin_remote_rm_usage, options);
remote = remote_get(argv[1]);
- if (!remote)
+ if (!remote_is_configured(remote))
die(_("No such remote: %s"), argv[1]);
known_remotes.to_delete = remote;
