line-log: suppress diff output with "-s"
When "-L" is in use, we ignore any diff output format that the user
provides to us, and just always print a patch (with extra context lines
covering the whole area of interest). It's not entirely clear what we
should do with all formats (e.g., should "--stat" show just the diffstat
of the touched lines, or the stat for the whole file?).
But "-s" is pretty clear: the user probably wants to see just the
commits that touched those lines, without any diff at all. Let's at
least make that work.
Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
diff --git a/t/t4211-line-log.sh b/t/t4211-line-log.sh
index bd5fe4d..c9f2036 100755
--- a/t/t4211-line-log.sh
+++ b/t/t4211-line-log.sh
@@ -115,4 +115,11 @@
git log $(for x in $(test_seq 200); do echo -L $((2*x)),+1:c.c; done)
'
+test_expect_success '-s shows only line-log commits' '
+ git log --format="commit %s" -L1,24:b.c >expect.raw &&
+ grep ^commit expect.raw >expect &&
+ git log --format="commit %s" -L1,24:b.c -s >actual &&
+ test_cmp expect actual
+'
+
test_done
