ls-tree: use "size_t", not "int" for "struct strbuf"'s "len"
The "struct strbuf"'s "len" member is a "size_t", not an "int", so
let's change our corresponding types accordingly. This also changes
the "len" and "speclen" variables, which are likewise used to store
the return value of strlen(), which returns "size_t", not "int".
Signed-off-by: Ævar Arnfjörð Bjarmason <avarab@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
diff --git a/builtin/ls-tree.c b/builtin/ls-tree.c
index 3f0225b..eecc748 100644
--- a/builtin/ls-tree.c
+++ b/builtin/ls-tree.c
@@ -31,7 +31,7 @@ static const char * const ls_tree_usage[] = {
NULL
};
-static int show_recursive(const char *base, int baselen, const char *pathname)
+static int show_recursive(const char *base, size_t baselen, const char *pathname)
{
int i;
@@ -43,7 +43,7 @@ static int show_recursive(const char *base, int baselen, const char *pathname)
for (i = 0; i < pathspec.nr; i++) {
const char *spec = pathspec.items[i].match;
- int len, speclen;
+ size_t len, speclen;
if (strncmp(base, spec, baselen))
continue;
@@ -65,7 +65,7 @@ static int show_tree(const struct object_id *oid, struct strbuf *base,
const char *pathname, unsigned mode, void *context)
{
int retval = 0;
- int baselen;
+ size_t baselen;
enum object_type type = OBJ_BLOB;
if (S_ISGITLINK(mode)) {
